document.write( "Question 571240: help with this question please:\r
\n" ); document.write( "\n" ); document.write( "(1/16)^-2v * 64=1 solve for v my teacher told me the answer is -3/4.\r
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Algebra.Com's Answer #368026 by Edwin McCravy(20065)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"%281%2F16%29%5E%28-2v%29\"·64 = 1\r\n" );
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document.write( "Learn the rule:  \"Flip the fraction, change the sign of the exponent\":\r\n" );
document.write( "That is, \"%28A%2FB%29%5E%28-C%29\" becomes \"%28B%2FA%29%5EC\"\r\n" );
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document.write( "\"%281%2F16%29%5E%28-2v%29\"·64 = 1\r\n" );
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document.write( "becomes\r\n" );
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document.write( "\"%2816%2F1%29%5E%282v%29\"·64 = 1\r\n" );
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document.write( "And we can dispense with the 1 denominator under the 16\r\n" );
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document.write( "   162v·64 = 1\r\n" );
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document.write( "Since 16 = 2·2·2·2 = 24 and since 64 = 2·2·2·2·2·2 = 26\r\n" );
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document.write( "(24)2v·26 = 1\r\n" );
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document.write( "Remove the parentheses by multiplying the exponent inside 4\r\n" );
document.write( "by the exponent outside 2v, getting an exponent of 8v\r\n" );
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document.write( "28v·26 = 1\r\n" );
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document.write( "Add the exponents\r\n" );
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document.write( "28v+6 = 1\r\n" );
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document.write( "We know that 0 is the only exponent 2 can have to give 1,\r\n" );
document.write( "since 20 = 1, so that means 8v+6 must equal 0.  So\r\n" );
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document.write( "8v + 6 = 0\r\n" );
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document.write( "    8v = -6\r\n" );
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document.write( "     v = \"-3%2F4\" \r\n" );
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document.write( "Edwin
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