document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54537>Question 54537</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618163832/algebrahomeworkh>McDougal Littell Algebra 1 concepts and skills</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> i do not understand how to even start this problem. it says:\r<BR>\n" );
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document.write( "With your new lawn mower, you can mow a lawn in 4 hours. With an older mower, your friend can mow the same lawn in 5 hours. How long will it take you to mow the lawn, working together?\r<BR>\n" );
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document.write( "HELP! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36799 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the rate at which each of you can mow the lawn:<BR>\n" );
document.write( "If you can mow the lawn in 4 hours, then you can mow 1/4 of the lawn in 1 hour.<BR>\n" );
document.write( "If your friend can mow the same lawn in 5 hours, then he/she can mow 1/5 of the lawn in 1 hour.<BR>\n" );
document.write( "So together, the two of you can mow 1/4 + 1/5 of the lawn in 1 hour.<BR>\n" );
document.write( "1/4 + 1/5 = (5+4)/20 = 9/20 of the lawn in 1 hour.<BR>\n" );
document.write( "So, it will take you both 20/9 hours to mow the lawn together.<BR>\n" );
document.write( "20/9 hours = 2 hrs and 13 1/3 minutes. </SPAN>\n" );
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