document.write( "Question 571111: factor completely\r
\n" ); document.write( "\n" ); document.write( "7x^2-7x^2y-28x+28xy
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Algebra.Com's Answer #367987 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
We can find common factors in groups of terms, and see what we end up with:
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\n" ); document.write( "If both factors in brackets were exactly the same, we would be finding a common factor again. We can fix that, because
\n" ); document.write( "\"%28-1%29%28-1%2By%29=%281-y%29\"
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\n" ); document.write( "and we can write that in more elegant ways, and even factor out a \"-7\"
\n" ); document.write( "\"%28%28-1%297x%5E2%2B28x%29%28-1%2By%29=%28-7x%5E2%2B28x%29%28y-1%29=-7%28x%5E2-4%29%28y-1%29\"
\n" ); document.write( "Because \"x%5E2-4=%28x%2B2%29%28x-2%29\", it can be factored too, to get to the full factorization.
\n" ); document.write( "\"-7%28x%5E2-4%29%28y-1%29=-7%28x%2B2%29%28x-2%29%28y-1%29\"
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