document.write( "Question 54537This question is from textbook McDougal Littell Algebra 1 concepts and skills
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document.write( ": i do not understand how to even start this problem. it says:\r
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document.write( "With your new lawn mower, you can mow a lawn in 4 hours. With an older mower, your friend can mow the same lawn in 5 hours. How long will it take you to mow the lawn, working together?\r
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document.write( "HELP! \n" );
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Algebra.Com's Answer #36798 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! With your new lawn mower, you can mow a lawn in 4 hours. With an older mower, your friend can mow the same lawn in 5 hours. How long will it take you to mow the lawn, working together? \n" ); document.write( "----------- \n" ); document.write( "New Mower DATA: \n" ); document.write( "Time to mow lawn = 4 hr/job ; rate= (1/4)job/hr. \n" ); document.write( "------------ \n" ); document.write( "Old Mower DATA: \n" ); document.write( "Time to mow lawn = 5 hr/job ;rate= (1/5) job/hr. \n" ); document.write( "-------------- \n" ); document.write( "Working together DATA: \n" ); document.write( "Time to mow lawn ; x hr/job ; rate = (1/x) job/hr. \n" ); document.write( "---------- \n" ); document.write( "EQUATION: \n" ); document.write( "new rate + old rate = together rate \n" ); document.write( "1/4 +1/5 = 1/x \n" ); document.write( "(9/20)=1/x \n" ); document.write( "x=20/9 \n" ); document.write( "x=2 2/9 hrs. or 2 hr 13 1/3 minutes (This is the time to mow the \n" ); document.write( "lawn when both mowers are used.) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |