document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=570149>Question 570149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A diameter is the segment from (-6,-4) to (3,5) ... Find the equation of the circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367942 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A diameter is the segment from (-6,-4) to (3,5) ... Find the equation of the circle.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius<BR>\n" );
document.write( "Finding mid points of x and y coordinates of given line segment end points:<BR>\n" );
document.write( "x=(3-6)/2=-3/2=-1.5<BR>\n" );
document.write( "y=(5-4)/2=12=.5<BR>\n" );
document.write( "center of circle: (-1.5,0.5)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Finding diameter of circle using distance formula:<BR>\n" );
document.write( "d^2=(3+6)^2+(5+4)^2=9^2+9^2=81+81=162<BR>\n" );
document.write( "d=&#8730;162<BR>\n" );
document.write( "radius=d/2=&#8730;162/2&#8776;6.36<BR>\n" );
document.write( "radius^2=40.5<BR>\n" );
document.write( "Equation of circle:<BR>\n" );
document.write( "(x+1.5)^2+(y-0.5)^2=40.5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );