document.write( "Question 571067: The length of a rectangular garden is 4 yd greater than the width. The area of the garden is 96 〖yd〗^2.Find the length and the width. \n" ); document.write( "

Algebra.Com's Answer #367939 by mananth(16946) $\"\"$ $\"About$

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width of garden = x yards
\n" ); document.write( "Length of garden = x+ 4 yards
\n" ); document.write( "
\n" ); document.write( "Area = L*W
\n" ); document.write( "Area= 96 sq. yards
\n" ); document.write( "Area = x(x+ 4 )
\n" ); document.write( "x(x+ 4 )= 96
\n" ); document.write( "
\n" ); document.write( "x^2 + 4 x = 96
\n" ); document.write( "x^2 + 4 x -96 = 0
\n" ); document.write( "x^2+ 12 x -8 x - -96 = 0
\n" ); document.write( "x(x+ 12 ) -8 (x+ 12 )= 0
\n" ); document.write( "(x+ 12 )(x -8 )= 0
\n" ); document.write( "
\n" ); document.write( "x= -12 OR 8
\n" ); document.write( "Ignore negative.
\n" ); document.write( "so x= 8
\n" ); document.write( "Width 8 yards
\n" ); document.write( "Length 12 yards (width + 4 )
\n" ); document.write( "m.ananth@hotmail.ca
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