document.write( "Question 571015: Here is the problem I'm stuck on...
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document.write( "A commercial jet travels 1,620 miles in the same amount of time that a corporate jet travels 1,260 miles. The rate of the commercial jet is 120 miles per hour faster than the rate of the corporate jet. Find the rate of each jet. \n" );
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Algebra.Com's Answer #367936 by mananth(16946) You can put this solution on YOUR website! Corporate jet B x mph \n" ); document.write( "Commercial jet A 120 faster \n" ); document.write( " \n" ); document.write( "Corporate jet 1260 miles \n" ); document.write( "Commercial jet 1620 miles \n" ); document.write( "Corporate jet time = Commercial jet time \n" ); document.write( " \n" ); document.write( "1260 / x = 1620 /( x + 120 \n" ); document.write( "cross multiply \n" ); document.write( "1260 ( x + 120 ) = 1620 x \n" ); document.write( "1260 x + 151200 = 1620 x \n" ); document.write( "1620 x - 1260 x = 151200 \n" ); document.write( "360 x = 151200 \n" ); document.write( "/ 360 \n" ); document.write( "x = 420 mph \n" ); document.write( "420 mph Corporate jet \n" ); document.write( "540 mph Commercial jet \n" ); document.write( " \n" ); document.write( " |