document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=571046>Question 571046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle in a triangle is one third as large as the first. The third angle is two thirds as large as the first angle. FInd the angle measures. Draw a picture of the triangle. Please help! I need to know how it is worked out and everything. Thanks in advance!! :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367917 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here is the equation you need to solve the question:\r<BR>\n" );
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document.write( "x + (x/3) + (2x/3) = 180\r<BR>\n" );
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document.write( "Let x = first angle\r<BR>\n" );
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document.write( "Let (x/3) = second angle\r<BR>\n" );
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document.write( "Let (2x/3) = third angle\r<BR>\n" );
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document.write( "When you find x, substitute x for each angle above to find all 3 angles of your triangle.\r<BR>\n" );
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