document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=571038>Question 571038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8xy^4 + 27x^4y factor completely, if prime state </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367911 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8xy^4 + 27x^4y =\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "xy(8y^3 + 27x^3) =\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "We now use the sum of cubes to factor the binomial in the parentheses.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "In the parentheses, we apply the formula \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(a^3 + b^3) = (a + b)(a^2 - 2b + b^2)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Then (8y^3 + 27x^3) becomes (2y + 3x)(4y^2 - 6xy + b^2).\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Final answer = xy(2y + 3x)(4y^2 - 6xy + b^2)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );