document.write( "Question 570943: What quantity of a 55% acid solution must be mixed with a 25% solution to produce 400 mL of a 40% solution? \n" ); document.write( "
Algebra.Com's Answer #367871 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Solution A \n" ); document.write( "Amount = x \n" ); document.write( "Concentration = 55%=0.55 \n" ); document.write( "Solution B \n" ); document.write( "Amount = 400-x \n" ); document.write( "Concentration = 25%=0.25 \n" ); document.write( "Resultant Solution \n" ); document.write( "Amount = 400 \n" ); document.write( "Concentration = 40% =0.4\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(Amount of A)(concentration of A)+ (Amount of B)(concentration of B)= (Amount of resultant)(concentration of resultant) \n" ); document.write( "(x)(0.55)+(400-x)(0.25)=(400)(0.4) \n" ); document.write( "0.55x+100-0.25x=160 \n" ); document.write( "0.55x-0.25x=160-100 \n" ); document.write( "0.3x=60 \n" ); document.write( "0.3x/0.3=60/0.3 \n" ); document.write( "x=200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "200ml of a 55% acid solution must be mixed with a 200ml of 25% solution to produce 400 mL of a 40% solution\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |