document.write( "Question 54534: √(6x+1)= x-1 Solve.\r
\n" ); document.write( "\n" ); document.write( "I got 6x+1=x^2-2x+1
\n" ); document.write( "Subtracted 6x and 1 and got 0=x^2-8x+0
\n" ); document.write( "x(x-8)
\n" ); document.write( "x=0
\n" ); document.write( "x=8
\n" ); document.write( "What did I do wrong?\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #36787 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
You need to check your answers with square root values.
\n" ); document.write( "sqrt(6 * 0 + 1) = 0 - 1
\n" ); document.write( "sqrt(1) = -1 Wrong *even though sqrt(1) = +- 1
\n" ); document.write( "sqrt(6 * 8 + 1) = 8 - 1
\n" ); document.write( "sqrt(49) = 7 True
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