document.write( "Question 54534: √(6x+1)= x-1 Solve.\r
\n" ); document.write( "\n" ); document.write( "I got 6x+1=x^2-2x+1
\n" ); document.write( "Subtracted 6x and 1 and got 0=x^2-8x+0
\n" ); document.write( "x(x-8)
\n" ); document.write( "x=0
\n" ); document.write( "x=8
\n" ); document.write( "What did I do wrong?\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #36786 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
√(6x+1)= x-1 Solve.
\n" ); document.write( "I got 6x+1=x^2-2x+1
\n" ); document.write( "Subtracted 6x and 1 and got 0=x^2-8x+0
\n" ); document.write( "x(x-8)
\n" ); document.write( "x=0
\n" ); document.write( "x=8
\n" ); document.write( "Now you have to check these answers to see if one
\n" ); document.write( "or both are extraneous.
\n" ); document.write( "Checking x=0 in the original problem you get:
\n" ); document.write( "sqrt(1)=-1. So x=0 is extraneous.
\n" ); document.write( "Checking x=8 in the original problem you get:
\n" ); document.write( "sqrt(49)=8-1=7
\n" ); document.write( "That is a good result. x=8 is your solution.
\n" ); document.write( "You might ask why you got an extraneous answer.
\n" ); document.write( "It happened when you squared both sides of the
\n" ); document.write( "equation. When you did that you introduced a
\n" ); document.write( "root that was not part of the original equation.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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