document.write( "Question 570923: The length of a rectangle is 6 feet less than twice the width. The perimeter is 48 feet. Find the length and width \n" ); document.write( "

Algebra.Com's Answer #367851 by JBarnum(2146) $\"\"$ $\"About$

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length(l) width(w) perimeter(p)
\n" ); document.write( "given:
\n" ); document.write( " $\"l=2w-6\"$
\n" ); document.write( " $\"p=48\"$
\n" ); document.write( " $\"2l%2B2w=p\"$
\n" ); document.write( ".
\n" ); document.write( " $\"2%282w-6%29%2B2w=48\"$ solve for w
\n" ); document.write( " $\"4w-12%2B2w=48\"$
\n" ); document.write( " $\"6w=60\"$
\n" ); document.write( " $\"w=10\"$
\n" ); document.write( ".
\n" ); document.write( " $\"l=2w-6\"$
\n" ); document.write( " $\"l=2%2810%29-6\"$
\n" ); document.write( " $\"l=14\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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