document.write( "Question 54362This question is from textbook Algebra Structure and Method
\n" ); document.write( ": Natalie has some nickels, Dirk has some dimes, and Quincy has some quateres. Dirk has five more dimes than Qunicy had quarters. If Natalie gives Dirk a nickel, Dirk gives Qunciy a dime, and Quincy gives Natalie a quater, they will all have the same amount of money. How many coins did each have orignially? \n" ); document.write( "
Algebra.Com's Answer #36782 by josmiceli(19441)\"\" \"About 
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n = number of Natalies nickels
\n" ); document.write( "d = number of Dirks dimes
\n" ); document.write( "q = number of Quincys quarters
\n" ); document.write( "5n + 10d + 25q = the sum of all their coins
\n" ); document.write( "d = q + 5
\n" ); document.write( "5n - 5 + 25 = 10d + 5 - 10 = 25q - 25 + 10
\n" ); document.write( "5n + 20 = 10d - 5 = 25q - 15
\n" ); document.write( "since d = q + 5
\n" ); document.write( "10(q + 5) - 5 = 25q - 15
\n" ); document.write( "10q + 45 = 25q - 15
\n" ); document.write( "15q = 60
\n" ); document.write( "q = 4 answer
\n" ); document.write( "d = q + 5
\n" ); document.write( "d = 9 answer
\n" ); document.write( "5n + 20 = 10d - 5
\n" ); document.write( "5n = 10*9 - 5 - 20
\n" ); document.write( "5n = 65
\n" ); document.write( "n = 13 answer
\n" ); document.write( "5n + 10d + 25q = the sum of all their coins
\n" ); document.write( "5*13 + 10*9 + 25*4 = 255
\n" ); document.write( "each person ends up with 255/3 = 85
\n" ); document.write( "5n + 20 = 5*13 + 20 = 85
\n" ); document.write( "10d - 5 = 10*9 - 5 = 85
\n" ); document.write( "25q - 15 = 25*4 - 15 = 85
\n" ); document.write( "so they all end up with an equal share
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