document.write( "Question 570844: find the equation that passes through the point (2,1) and perpendicular to the line y=5x-3
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Algebra.Com's Answer #367802 by mananth(16946)\"\" \"About 
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1 y = 5 x -3
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\n" ); document.write( " y = 5 x -3
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = 5
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal - 1/5
\n" ); document.write( "m1*m2=-1
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\n" ); document.write( "m= - 1/5 ,point ( 2 , 1 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "1 = -2/5 + b
\n" ); document.write( "b= 7/5
\n" ); document.write( "m= - 1/5
\n" ); document.write( "The required equation is y = - 1/ 5 x + 7/ 5
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