document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=570802>Question 570802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many kilos of tea worth Rs.72 per kg should be mixed with 10kg of tea worth Rs.90 per kg to produce a mixture which will cost Rs.78 per kg </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367788 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ----------------	Price	----------------	quantity									<BR>\n" );
document.write( "Tea type I  	90	----------------10	pounds						<BR>\n" );
document.write( "Tea type II 	72	----------------x	pounds						<BR>\n" );
document.write( "Mixture	78	----------------	10+x	pounds						<BR>\n" );
document.write( "												<BR>\n" );
document.write( "sum of individual components = quantity in mixture												<BR>\n" );
document.write( "90*10+72x=78(10	+x)<BR>\n" );
document.write( "900+72x	=780+78	x				<BR>\n" );
document.write( "72x -78	x=-120							<BR>\n" );
document.write( "-6x=-120									<BR>\n" );
document.write( "	x=	-120	/	-6								<BR>\n" );
document.write( "	x=	20										<BR>\n" );
document.write( "20	pounds	of 	Tea type II 	costing	Rs.	72	has to be added					<BR>\n" );
document.write( "m.ananth@hotmail.ca												<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );