document.write( "Question 570786: The perimeter of a rectangle is 2012, and lengths of all sides are integers. What is the smallest possible area of this rectangle? \n" ); document.write( "
Algebra.Com's Answer #367787 by KMST(5328)\"\" \"About 
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If \"x\" and \"y\" are the dimensions of this rectangle, we know that
\n" ); document.write( "\"2%28x%2By%29=2012\" so \"x%2By=2012%2F2\" \"x%2By=1006\" and \"y=1006-x\"
\n" ); document.write( "The area, as a function of x is
\n" ); document.write( "\"A%28x%29=%281006-x%29x\"
\n" ); document.write( "\"A%28x%29=-x%5E2%2B1006x\"
\n" ); document.write( "That quadratic equation represents a parabola.
\n" ); document.write( "Its axis of symmetry is \"x=-1006%2F%282%2A%28-1%29%29\" \"x=503\"
\n" ); document.write( "The maximum area occurs at \"x=503\", when the rectangle is a square.
\n" ); document.write( "Moving away from that point, to either side of \"x=503\", the area decreases.
\n" ); document.write( "Since the length of the sides are integers, the minimum will be for \"x=1\" and \"x=1005\", when one side measures 1 and the other 1005. It is the same solutionm no matter what side length we call x.
\n" ); document.write( "The minimum area is 1005.
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