document.write( "Question 570792: Perpendicular to y= 1/3x + 2; (3,3) \n" ); document.write( "

Algebra.Com's Answer #367776 by mananth(16946) $\"\"$ $\"About$

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1 y = 1/3 x + 2
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = 1/ 3 x + 2
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = 1/ 3
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal -3
\n" ); document.write( "m1*m2=-1
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\n" ); document.write( "m= -3 ,point ( 3 , 3 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "3 = -9 + b
\n" ); document.write( "b= 12
\n" ); document.write( "m= -3
\n" ); document.write( "The required equation isy =-3x + 12
\n" ); document.write( "m.ananth@hotmail.ca
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