document.write( "Question 570735: I've been trying to help my daughter, but it's been too long since I've done any algebra. She is currently in graphs, but this does not seem to fit. Anyway, here is the question posed.
\n" ); document.write( "A rectangular hole 2cm wide and x cm long is cut in a rectangular sheet of metal 7/2cm wide and y cm long. The length of the hole is 1 cm less than the length of the metal sheet. After the hole is cut, the area of the remaining metal is 11cm squared. Find the length of the hole and the length of the metal sheet.
\n" ); document.write( "I'm math stupid and having a difficult time trying to find help.
\n" ); document.write( "Thank you for any suggestions,
\n" ); document.write( "Jeff R. \n" ); document.write( "

Algebra.Com's Answer #367746 by scott8148(6628) $\"\"$ $\"About$

You can put this solution on YOUR website!
\"The length of the hole is 1 cm less than the length of the metal sheet\" ___ x + 1 = y\r
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\n" ); document.write( "\n" ); document.write( "\"After the hole is cut, the area of the remaining metal is 11cm squared\" ___ (2*x) + 11 = (7/2)*y\r
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\n" ); document.write( "\n" ); document.write( "substituting ___ 2x + 11 = (7/2)(x + 1) ___ 2x + 11 = (7/2)x + (7/2) ___ 4x + 22 = 7x + 7\r
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\n" ); document.write( "\n" ); document.write( "solve for x, then substitute back to find y \n" ); document.write( "

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