document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=570626>Question 570626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the area of a triangle with the sides 33,30 and 23. (I can NOT use Herons formula or the law of sine or cosines to find it btw. Its an extra credit problem and I need help : / </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367742 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the longest side as the base\r<BR>\n" );
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document.write( "the altitude (h) divides the triangle into two right triangles; a, h, 30 and b, h ,23\r<BR>\n" );
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document.write( "a + b = 33\r<BR>\n" );
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document.write( "a^2 + h^2 = 30^2\r<BR>\n" );
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document.write( "b^2 + h^2 = 23^3\r<BR>\n" );
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document.write( "three equations, three unknowns\r<BR>\n" );
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document.write( "subtracting 2nd and 3rd equations ___ a^2 - b^2 = 30^2 - 23^2 ___ (a + b)(a - b) = 371\r<BR>\n" );
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document.write( "dividing by 1st equation ___ a - b = 371 / 33\r<BR>\n" );
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document.write( "adding 1st equation ___ a - b + a + b = 33 + (371 / 33) ___ 2a = 1460 / 33\r<BR>\n" );
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document.write( "solve for a, then substitute back to find h </SPAN>\n" );
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