document.write( "Question 570645: Solve the equation by factoring.\r
\n" ); document.write( "\n" ); document.write( "(2x/x+3)+(5/x)-4=(18/x^2+3x)
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\n" ); document.write( "I have gotten this far with the problem....
\n" ); document.write( "LCM = X(x+3) thus I have 2x^2+5x+15-4x^2-12=18--->-2x^2+5x+3=18--->-2x^2+5x-15=0\r
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\n" ); document.write( "\n" ); document.write( "I think my problem is the (-2x^2) which I got from 2x^2-4x^2 and the (-4x^2) is from multiplying the LCM (x(x+3))to -4.\r
\n" ); document.write( "\n" ); document.write( "Could you show me where my error is?\r
\n" ); document.write( "\n" ); document.write( "Thank you \r
\n" ); document.write( "\n" ); document.write( "Kenneth
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Algebra.Com's Answer #367725 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "\"%282x%29%2F%28x%2B3%29%2B5%2Fx+-4+=+18%2F%28x%5E2%2B3x%29\" Simplify. The LCD is\"x%5E2%2B3x\"
\n" ); document.write( " so we have:
\n" ); document.write( "\"-2x%5E2-7x%2B15+=+18\" Subtract 18 from both sides.
\n" ); document.write( "\"-2x%5E2-7x-3+=+0\" Multiply through by -1 to get:
\n" ); document.write( "\"2x%5E2%2B7x%2B3+=+0\" Factor.
\n" ); document.write( "\"%282x%2B1%29%28x%2B3%29+=+0\" Apply the zero product rule:
\n" ); document.write( "\"2x%2B1+=+0\" or \"x%2B3+=+0\" so...
\n" ); document.write( "\"x+=+-1%2F2\" or \"x+=+-3\"
\n" ); document.write( "Notice: The left side becomes...
\n" ); document.write( "\"%282x%28x%29%2B5%28x%2B3%29-4%28x%28x%2B3%29%29%29%2Fx%28x%2B3%29\" which, when simplified becomes:
\n" ); document.write( "\"%282x%5E2%2B5x%2B15-4x%5E2-12x%29%2Fx%28x%2B3%29\"=\"%28-2x%5E2-7x%2B15%29%2F%28x%5E2%2B3x%29\"
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