document.write( "Question 570107: Cristina found out that the total electrical resistance of R of two resistors connected in parallel is given by 1/R=1/R1+1/R2. The total resistance is 12.3 ohms. Let 2x-1=R1.
\n" ); document.write( "A. Express the second resistance R2 as a function of x.
\n" ); document.write( "B. Find R2 if x is : ohms.
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Algebra.Com's Answer #367710 by ankor@dixie-net.com(22740)\"\" \"About 
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\"1%2FR\"=\"1%2FR1%2B1%2FR2\".
\n" ); document.write( " The total resistance is 12.3 ohms. Let 2x-1=R1.
\n" ); document.write( "\"1%2F12.3\"=\"1%2F%282x-1%29%2B1%2FR2\".
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\n" ); document.write( "A. Express the second resistance R2 as a function of x.
\n" ); document.write( "\"1%2F12.3\"=\"1%2F%282x-1%29%2B1%2FR2\"
\n" ); document.write( "Lets simplify things here
\n" ); document.write( "Let a = R1 = (2x-1)
\n" ); document.write( "Let b = R2
\n" ); document.write( "Rewrite the equation to
\n" ); document.write( "\"1%2F12.3\"=\"1%2Fa\" + \"1%2Fb\".
\n" ); document.write( "Multiply thru by 12.3ab
\n" ); document.write( "12.3ab*\"1%2F12.3\"= 12.3ab*\"1%2Fa\" + 12.3ab*\"1%2Fb\"
\n" ); document.write( "cancel the denominators, results
\n" ); document.write( "ab = 12.3b + 12.3a
\n" ); document.write( "Get b in terms of a
\n" ); document.write( "ab - 12.3b = 12.3a
\n" ); document.write( "Factor out b on the left
\n" ); document.write( "b(a-12.3) = 12.3a
\n" ); document.write( "b = \"%2812.3a%29%2F%28%28a-12.3%29%29\"
\n" ); document.write( "Replace a with (2x-1), and b with R2
\n" ); document.write( "R2 = \"%2812.3%282x-1%29%29%2F%28%28%282x-1%29-12.3%29%29\"
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\n" ); document.write( "R2 = \"%2824.6x-12.3%29%2F%282x-13.3%29\"; is R2 in terms of x
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\n" ); document.write( "B. Find R2 if x is : ohms. You didn't give any value for x, you can find what that is and substitute it for x in the above, to find R2
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