document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=570609>Question 570609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a boat is traveling downstream to a destination and it takes 40 minutes in a 3 mph current. Traveling the same distance going upstream with 3mph current it takes 60 minutes. How fast would the boat be traveling in still water?\r<BR>\n" );
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document.write( "I'm not even sure how to go about this but I think going downhill the boat is going 13.3mph and uphill the boat is having to go 20mph? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367708 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367708\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Boat speed	=x	mph									<BR>\n" );
document.write( "current speed 	3	mph									<BR>\n" );
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document.write( "time with current	0.67	hours									<BR>\n" );
document.write( "time against current 	1	hours	\r<BR>\n" );
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document.write( "0.67(x+3)=1(x-3)<BR>\n" );
document.write( "0.67x+	2.00	=1x-3				<BR>\n" );
document.write( "1	x	-0.67	x	=	2	+	3			<BR>\n" );
document.write( "0.33	x  	=	5							<BR>\n" );
document.write( "x 	=	15	mph	Boat speed						<BR>\n" );
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