document.write( "Question 570598: I do not really understand how to do this...\r
\n" ); document.write( "\n" ); document.write( "sqrt(3x+17) - 5 = x\r
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Algebra.Com's Answer #367706 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%283x%2B17%29+-+5+=+x\"\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%283x%2B17%29+=+x%2B5\"\r
\n" ); document.write( "\n" ); document.write( "square both side of the equation\r
\n" ); document.write( "\n" ); document.write( "\"3x%2B17+=+%28x%2B5%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B17+=+x%5E2%2B10x%2B25\"\r
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\n" ); document.write( "\n" ); document.write( "x^2+7x+8=0\r
\n" ); document.write( "\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 1 b= 7 c= 8
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\n" ); document.write( "b^2-4ac= 49 - -32
\n" ); document.write( "b^2-4ac= 17
\n" ); document.write( "\"sqrt%28%0917%09%29\"= 4.12
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( -7 + 4.12 )/ 2
\n" ); document.write( "x1= -1.44
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\n" ); document.write( "x2=( -7 -4.12 ) / 2
\n" ); document.write( "x2= -5.56 \r
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