document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=570222>Question 570222</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hey how would you solve this problem: select the expression below that is identical to tan(-x)tan(pi/2-x). and here are the choices: A. 1, B. tan squared x, C. -1, D. 2sin squared x, E. 2csc squared x. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367697 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> hey how would you solve this problem: select the expression below that is identical to tan(-x)tan(pi/2-x). and here are the choices: A. 1, B. tan squared x, C. -1, D. 2sin squared x, E. 2csc squared x. <BR>\n" );
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document.write( "-&#960;/2 < x < &#960;/2<BR>\n" );
document.write( "tan(-x) is in quadrant IV where tan<0<BR>\n" );
document.write( "tan(&#960;/2-x)is in quadrant I where tan>0<BR>\n" );
document.write( "(&#960;/2-x) is the complement of (-x) (reference angles)<BR>\n" );
document.write( "tan(x)*tan(complement of x)=1<BR>\n" );
document.write( "Therefore,  tan(-x)tan(&#960;/2-x)=-1<BR>\n" );
document.write( "correct answer is C<BR>\n" );
document.write( "Note: This example is for (-&#960;/2 < x < &#960;/2) but it will also be true for the full range of (0-2&#960;) </SPAN>\n" );
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