document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=570089>Question 570089</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having issues with this one problem in my home work. I don't know why I cant get it...We have to set it up in the 5 step and I guess I am just confused. \r<BR>\n" );
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document.write( "?. The perimeter of a rectangle is 36m. The length is 2m more than three thimes the width. Find the length and with of the rectangle. \r<BR>\n" );
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document.write( "Ok, so here is what I have done.<BR>\n" );
document.write( "Data: I drew a rectangle with the length labeled as 3w + 2, and the width is just labeled as w. \r<BR>\n" );
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document.write( "Varaibles: P=2(3w+2)x 2w<BR>\n" );
document.write( "Plan: P=2Lx2W<BR>\n" );
document.write( "Equation: 36=2(3w+2)x 2w\r<BR>\n" );
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document.write( "Ok...so here is where I get stuck. <BR>\n" );
document.write( "36=2(3w+2) x 2w<BR>\n" );
document.write( "36=6w+4 x 2w\r<BR>\n" );
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document.write( "so I think now I subtract 4 from each side, but then I am stuck. Am I even close?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367642 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think you have the right idea, let's do it this way<BR>\n" );
document.write( "Write an equation for each statement:<BR>\n" );
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document.write( "\"The perimeter of a rectangle is 36m.\"<BR>\n" );
document.write( "2L + 2W = 36<BR>\n" );
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document.write( "\"The length is 2m more than three times the width.\"<BR>\n" );
document.write( "L = 3W + 2<BR>\n" );
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document.write( "Replace L in the 2st equation with (3W+2); resulting in<BR>\n" );
document.write( "2(3W+2) + 2W = 36<BR>\n" );
document.write( "6W + 4 + 2W = 36: this is essentially what you did, just combine like terms, find W<BR>\n" );
document.write( "8W = 36 - 4<BR>\n" );
document.write( "8W = 32<BR>\n" );
document.write( "W = 32/8<BR>\n" );
document.write( "W = 4 m is the width<BR>\n" );
document.write( "the<BR>\n" );
document.write( "L = 3(4) + 2<BR>\n" );
document.write( "L = 14 m is the length<BR>\n" );
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document.write( "Check our solutions by finding the perimeter with these values<BR>\n" );
document.write( "2(14) + 2(4) =<BR>\n" );
document.write( "28 + 8 = 36\r<BR>\n" );
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