document.write( "Question 570204: the perimeter of a rectangle is 54 m. The width is 3 m less than twice the length. Find the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #367614 by JBarnum(2146)\"\" \"About 
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GIVEN:
\n" ); document.write( "2W+2L=P
\n" ); document.write( "P=54
\n" ); document.write( "W=2L-3
\n" ); document.write( ",
\n" ); document.write( "SOLVE:
\n" ); document.write( "substitution
\n" ); document.write( "2(2L-3)+2L=54
\n" ); document.write( "4L-6+2L=54
\n" ); document.write( "6L=60
\n" ); document.write( "L=10
\n" ); document.write( ".
\n" ); document.write( "W=2L-3
\n" ); document.write( "W=2(10)-3
\n" ); document.write( "W=20-3
\n" ); document.write( "W=17\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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