document.write( "Question 570151: Find the equation of the line passing through (-1,1) and parallel to x+2y-13=0. Give answer in slope-intercept form. (y=mx+b) \n" ); document.write( "
Algebra.Com's Answer #367612 by nerdybill(7384)\"\" \"About 
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Find the equation of the line passing through (-1,1) and parallel to x+2y-13=0. Give answer in slope-intercept form. (y=mx+b)
\n" ); document.write( "Begin by determining slope of:
\n" ); document.write( "x+2y-13=0
\n" ); document.write( "2y-13=-x
\n" ); document.write( "2y=-x+13
\n" ); document.write( "y=(-1/2)x + 13/2
\n" ); document.write( "slope is -1/2
\n" ); document.write( ".
\n" ); document.write( "plug slope (-1/2) and given point (-1,1) into \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - 1 = (-1/2)(x - (-1))
\n" ); document.write( "y - 1 = (-1/2)(x + 1)
\n" ); document.write( "y - 1 = (-1/2)x - 1/2
\n" ); document.write( "y = (-1/2)x - 1/2 + 1
\n" ); document.write( "y = (-1/2)x - 1/2 + 2/2
\n" ); document.write( "y = (-1/2)x + 1/2 (this is what they're looking for)\r
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