document.write( "Question 570100: Given the menu below how many different burgers can you make. Meat: single meat, double meat, and triple meat. Cheese: there are 3 different kinds (you can use a max of 3 cheeses). Toppings: there are 13 different kinds of toppings.\r
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document.write( "Note: a combination is counted by what is on the burger NOT the order of placement.....Wouldn't you solve this by multiplying 3*3*13??? \n" );
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Algebra.Com's Answer #367591 by richard1234(7193) You can put this solution on YOUR website! It is probably assumed that you can use any of the 13 toppings. Therefore the number of ways is 3*3*(2^13) because for each topping you can either put it on or not put it on, for two possibilities. There are 13 toppings, so 2^13. \n" ); document.write( " |