document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=570166>Question 570166</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I work this? I am drawing a blank. Thank You for any help.\r<BR>\n" );
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document.write( "sin &#952; = - ½ , 180° < 0 < 270°, find tan &#952;  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367583 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin &#952; = - ½ , 180° < 0 < 270°, find tan &#952; <BR>\n" );
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document.write( "Theta is in the 3rd Quadrant where x and y are both negative.<BR>\n" );
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document.write( "Since sin = y/r, y = -1 and r = 2<BR>\n" );
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document.write( "solve for \"x\":<BR>\n" );
document.write( "2^2 = (-1)^2 + x^2<BR>\n" );
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document.write( "x = -sqrt(3) (negative because theta is in the 3rd quadrant)<BR>\n" );
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document.write( "Then tan(theta) = y/x = -1/(-sqrt(3)) = 1/sqrt(3) = (1/3)sqrt(3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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