document.write( "Question 570085: I do not understand how to work these problems, I am pretty good at algebra but i do not understand what formula to use or how to work through them, any help is appreciated.\r
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document.write( "The radiator in a certain make of car needs to contain 70 liters of 40% antifreeze. the radiator now contains 70 liters of 20% antifreeze. How many liters of this solvent must be drained and replaced with 00% antifreeze to get the desired strength?
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Algebra.Com's Answer #367571 by KMST(5328)![]() ![]() You can put this solution on YOUR website! If the radiator has 20% antifreeze now and it needs 40%, you may need to replace some of the liquid with 100% antifreeze (not 00%, which I think is some kind of typo). \n" ); document.write( "This kind of problem requires that you do some accounting of both, the total volume, and the amount of the substance of interest that is mixed in. \n" ); document.write( "The total volume you need is 70 L. \n" ); document.write( "The total amount of antifreeze that you need in those 70 L is \n" ); document.write( " \n" ); document.write( "If you remove \n" ); document.write( "The final amount of antifreeze in there will be \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So we need to find the \n" ); document.write( " |