document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=569126>Question 569126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given log(base a)5 = 2.32, and log(base a)9=3.17, find log(base a) 25/9= amd find log(base a) radical 45 = </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367569 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367569\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given log(base a)5 = 2.32, and log(base a)9=3.17, find log(base a) 25/9= amd find log(base a) radical 45 =<BR>\n" );
document.write( "**<BR>\n" );
document.write( "log(base a)=loga<BR>\n" );
document.write( "loga(25/9)=loga(5^2/9)=2loga(5)-loga(9)=2*2.32-3.17=1.47<BR>\n" );
document.write( "loga(&#8730;45)=loga(45^.5)=.5loga(45)=.5loga(5*9)=.5(loga(5)+loga(9))=.5(2.32+3.17)=2.745 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );