document.write( "Question 569232: e^(2x+1)-10=62 \n" ); document.write( "
Algebra.Com's Answer #367568 by lwsshak3(11628)\"\" \"About 
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e^(2x+1)-10=62
\n" ); document.write( "e^(2x+1)=72
\n" ); document.write( "take log of both sides
\n" ); document.write( "(2x+1)lne=ln72
\n" ); document.write( "lne=1
\n" ); document.write( "2x+1=ln72
\n" ); document.write( "2x=ln72-1
\n" ); document.write( "x=(ln72-1)/2
\n" ); document.write( "using calculator
\n" ); document.write( "x≈1.6383
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