document.write( "Question 568252: identify the conic represented by x^2-4y-6x+9=0 \n" ); document.write( "
Algebra.Com's Answer #367549 by lwsshak3(11628)\"\" \"About 
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identify the conic represented by x^2-4y-6x+9=0
\n" ); document.write( "complete the square
\n" ); document.write( "(x^2-6x+9)-4y+9-9=0
\n" ); document.write( "4y=(x-3)^2
\n" ); document.write( "y=(1/4)(x-3)^2
\n" ); document.write( "This is an equation for a parabola with vertex at (3,0)
\n" ); document.write( "Parabola opens upwards with minimum=0.
\n" ); document.write( "Standard form of equation for given parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the slope or steepness of the curve.
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