document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=569738>Question 569738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> prove step-by-step that:<BR>\n" );
document.write( "(secx-1/tanx) + (tanx/secx+1) = (2sinx/1+cosx)\r<BR>\n" );
document.write( "\n" );
document.write( "This is really important, any help ASAP would be awesome, thank you!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367546 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> prove step-by-step that:<BR>\n" );
document.write( "(secx-1/tanx) + (tanx/secx+1) = (2sinx/1+cosx) <BR>\n" );
document.write( "start with left side<BR>\n" );
document.write( "(secx-1/tanx) + (tanx/secx+1)<BR>\n" );
document.write( "add terms<BR>\n" );
document.write( "[(secx-1)(secx+1)+tanx*tanx]/tanx(secx+1)<BR>\n" );
document.write( "=[(sec^2x-1)+tan^2x]/tanx(secx+1)<BR>\n" );
document.write( "=[tan^2x+tan^2x]/tanx(1/cosx+1)<BR>\n" );
document.write( "=2tan^2x/tanx(1+cosx)/(cosx)<BR>\n" );
document.write( "=2tanx/(1+cosx)/(cosx)<BR>\n" );
document.write( "=2tanxcosx/1+cosx<BR>\n" );
document.write( "=2(sinx/cosx)*cosx/(1+cosx)<BR>\n" );
document.write( "=2sinx/(1+cosx)<BR>\n" );
document.write( "verified: left side=right side </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );