document.write( "Question 570109: A sum amounting to $3.35 consists of quarters and dimes. If there are 23 coins in all how many are quarters? \n" ); document.write( "
Algebra.Com's Answer #367544 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Total Sum of coins = $3.35 \n" ); document.write( "Total Coins = 23 \n" ); document.write( "Dimes = x \n" ); document.write( "Quarters = 23-x \n" ); document.write( "Value of a Dime = $0.1 \n" ); document.write( "Value of a Quarter =$0.25\r \n" ); document.write( "\n" ); document.write( "(value of a Dime)(Dimes)+(value of a Quarter)(Quarters)=Total Sum of Coins \n" ); document.write( "(0.1)(x)+(0.25)(23-x)=3.35 \n" ); document.write( "0.1x+5.75-0.25x=3.35 \n" ); document.write( "0.1x-0.25x=3.35-5.75 \n" ); document.write( "-0.15x=-2.4 \n" ); document.write( "-0.15x/-0.15=-2.4/-0.15 \n" ); document.write( "x=16\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dimes = x = 16 \n" ); document.write( "Quarters = 23-x = 23-16 = 7\r \n" ); document.write( "\n" ); document.write( "There are 7 Quarters \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "====== \n" ); document.write( "(0.1)(16)+(7)(0.25)=3.35 \n" ); document.write( "1.6+1.75=3.35 \n" ); document.write( "3.35=3.35 \n" ); document.write( " \n" ); document.write( " |