document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54499>Question 54499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am stuck on correct answer for:\r<BR>\n" );
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document.write( "4y^2 - 6y   over 2y  =\r<BR>\n" );
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document.write( "I am not using any specific book. I am just practicing... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36751 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4Y^2-6Y)/2Y OR FACTOR OUT 2Y FROM THE NUMERATOR 2Y(2Y-3)/2Y NOW DIVIDE BOTH NUMERATOR OR DENOMINATOR BY 2Y WE GET 2Y-3 </SPAN>\n" );
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