document.write( "Question 569409: 3(y-3)=(x-6)^2
\n" ); document.write( "What steps do I need to do in order to make that equation to y=a(x-h)^2 +k form ?
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Algebra.Com's Answer #367460 by lwsshak3(11628)\"\" \"About 
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3(y-3)=(x-6)^2
\n" ); document.write( "What steps do I need to do in order to make that equation to y=a(x-h)^2 +k form
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\n" ); document.write( "3(y-3)=(x-6)^2
\n" ); document.write( "3y-9=x^2-12x+36
\n" ); document.write( "3y=x^2-12x+45
\n" ); document.write( "divide by 3
\n" ); document.write( "y=(1/3)x^2-4x+15
\n" ); document.write( "complete the square
\n" ); document.write( "y=(1/3)(x^2-4x+4)+15-4/3
\n" ); document.write( "y=(1/3)(x-2)^2+41/3
\n" ); document.write( "a=1/3, h=2, k=41/3
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