document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=569577>Question 569577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To pass a course, corrina needs an average score of 60 or more. If Corina 's scores are 66 72 90 49 and 59 find the minimum score that maria can get on her sixth and last exam and pass the sourse. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367368 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To pass a course, corrina needs an average score of 60 or more. If Corina 's scores are 66 72 90 49 and 59 find the minimum score that maria can get on her sixth and last exam and pass the sourse.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let  x = minimum score on sixth exam<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(66+72+90+49+59+x)/6 = 60<BR>\n" );
document.write( "(336+x)/6 = 60<BR>\n" );
document.write( "336+x = 360<BR>\n" );
document.write( "x = 24<BR>\n" );
document.write( " </SPAN>\n" );
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