document.write( "Question 569506: Two cyclists, 48 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist? \n" ); document.write( "

Algebra.Com's Answer #367350 by josmiceli(19441) $\"\"$ $\"About$

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They are approaching each other at the sum of their speeds
\n" ); document.write( "Think of one ( either one ) as standing still and the
\n" ); document.write( "other moving at the sum of their speeds
\n" ); document.write( "Call the speed of the faster one $\"+3s+\"$
\n" ); document.write( "The speed of the slower one is $\"+s+\"$
\n" ); document.write( "I can say $\"+48+=+%28+3s+%2B+s+%29%2A2+\"$
\n" ); document.write( " $\"+48+=+6s+%2B+2s+\"$
\n" ); document.write( " $\"+8s+=+48+\"$
\n" ); document.write( " $\"+s+=+6+\"$
\n" ); document.write( " $\"+3s+=+18+\"$
\n" ); document.write( "The speed of the faster cyclist is 18 mi/hr \n" ); document.write( "

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