document.write( "Question 569517: 6300 is invested part of it at 11% and part of it at 8% for a certain year the total yield is 597.00. how much was invested at each rate\r
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document.write( "How much was invested at 11% and 8% \n" );
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Algebra.Com's Answer #367343 by bluemockingjay7(41)![]() ![]() You can put this solution on YOUR website! x = P1 r1 = 11% = .11 \n" ); document.write( "6300 - x = P2 r2 = 8% = .08\r \n" ); document.write( "\n" ); document.write( "x(.08) + (6300 - x)(.11) = 597 \n" ); document.write( ".08x + 693 - .11x = 597 \n" ); document.write( ".08x - .11x = 597 - 693 \n" ); document.write( "-.03x = -96 \n" ); document.write( "-.03x/-.03 = -96/-.03 \n" ); document.write( "x = 3200\r \n" ); document.write( "\n" ); document.write( "invested at 11% = 3200 \n" ); document.write( "invested at 8% = 6300 - 3200 = 3100 \n" ); document.write( " |