document.write( "Question 569139: Jose left the airport and traveled toward the mountains. Kayla left 2.1 hours later traveling 35 mph faster in an effort to catch up to him. After 1.2 hours, Kayla finally caught up. Find Jose's average speed. \n" ); document.write( "
Algebra.Com's Answer #367307 by ankor@dixie-net.com(22740)\"\" \"About 
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Kayla left 2.1 hours later traveling 35 mph faster in an effort to catch up to him.
\n" ); document.write( "After 1.2 hours, Kayla finally caught up. Find Jose's average speed.
\n" ); document.write( ":
\n" ); document.write( "From the information given:
\n" ); document.write( "1.2 hrs is K's travel time (sorry about that)
\n" ); document.write( "and
\n" ); document.write( "2.1 + 1.2 = 3.3 hrs is J's travel time
\n" ); document.write( ":
\n" ); document.write( "When K catches, J, they will have traveled the same distance.
\n" ); document.write( "Let j = J's speed
\n" ); document.write( "then
\n" ); document.write( "(j+35) = K's speed
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation: Dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "3.3j = 1.2(j+35)
\n" ); document.write( "3.3j = 1.2j + 42
\n" ); document.write( "3.3j - 1.2j = 42
\n" ); document.write( "2.1j = 42
\n" ); document.write( "j = 42/2.1
\n" ); document.write( "j = 20 mph is J's average speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the distance each traveled, they should be equal
\n" ); document.write( "3.3(20) = 66 mi
\n" ); document.write( "1.2(55) = 66 mi \n" ); document.write( "
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