document.write( "Question 6671: How do you solve this function of operations:
\n" ); document.write( "Given:f(x) = x^2 - 4 (x squared minus 4) and g(x) = radical 2x + 4
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\n" ); document.write( "\n" ); document.write( "I understand that I have to plug in g(x) into f(x) but I don't understand the part about the Domain. Please help me. Thanks.
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Algebra.Com's Answer #3673 by prince_abubu(198)\"\" \"About 
You can put this solution on YOUR website!
I'm thinking that you meant \"+g%28x%29+=+sqrt%282x+%2B+4%29+\". If you plug that into f(x), you'll get:\r
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\n" ); document.write( "\n" ); document.write( "\"+f%28g%28x%29%29+=+2x+\" <---- The domain would have to be the set of values that you could plug into f(g(x)) legally. In other words, what values of x can we put into the function so that none of those values will make a denominator zero, or whatever inside the square root \"house\" negative. In this case, you can choose any x value you want, since you can multiply 2 times any number.\r
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\n" ); document.write( "\n" ); document.write( "Say that you meant \"+g%28x%29+=+sqrt%282x%29+%2B+4+\". If you plug that into f(x), you'll get:\r
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\n" ); document.write( "\n" ); document.write( "\"+f%28g%28x%29%29+=+%28g%28x%29%29%5E2+-+4+=+%28sqrt%282x%29+%2B+4%29%5E2+-+4+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+f%28g%28x%29%29+=+%28sqrt%282x%29+%2B+4%29%28sqrt%282x%29+%2B+4%29+-+4+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+f%28g%28x%29%29+=+%28sqrt%282x%29%29%5E2+%2B+8sqrt%282x%29+%2B+16+-+4+\" <--- Used FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"+f%28g%28x%29%29+=+2x+%2B+8sqrt%282x%29+%2B+12+\" <---- Simplified.\r
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\n" ); document.write( "\n" ); document.write( "Now, what's the domain of f(g(x)) in that case? It would be all real numbers x greater than or equal to zero. You can't plug in negative numbers into that function because doing so will force the 2x inside \"+8sqrt%282x%29+\" to be a negative number, which you can't do inside square roots.
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