document.write( "Question 569330: With A and B as centers and a radius how would you construct a perpendicular to the line AB? \n" ); document.write( "

Algebra.Com's Answer #367283 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Assuming the measure of the radius is strictly greater than the measure of AB divided by 2, construct a circle of the radius centered at A and then construct another circle with the same radius centered at B. The two circles will intersect at two points. Construct a line segment passing through the two points of intersection. The fact that each of the points is equidistant from A and B guarantees that the constructed segment will not only be perpendicular to AB, but will also bisect AB.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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