document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=569226>Question 569226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me prove: <BR>\n" );
document.write( "-a = (-1)*a\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367264 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -a = (-1)*a <BR>\n" );
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document.write( "You need to show the (-1)a is the additive inverse of \"a\".<BR>\n" );
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document.write( "a + (-1)a = (1+(-1))a ; Distributive Law\r<BR>\n" );
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document.write( "=  0*a = 0 ; Definition of additive inverse.<BR>\n" );
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document.write( "Therefore (-1)a is the additive inverse of a ; Definition of additive inverse.<BR>\n" );
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document.write( "Therefore (-1)a = -a ; Def. of equality<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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