document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=569130>Question 569130</A>: <I><SPAN STYLE=\"word-break: break-all;\"> it is necessary to have a 70% antifreeze solution in a radiator of a certain car. the radiator now has 20 ml of 60%  solution. how much of this solution should be drained and replaced with 100% antifreeze to get the desired strength </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367245 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> it is necessary to have a 70% antifreeze solution in a radiator of a certain car. the radiator now has 20 ml of 60% solution. how much of this solution should be drained and replaced with 100% antifreeze to get the desired strength.<BR>\n" );
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document.write( "x=ml of 60% solution to be drained and replaced with 100% antifreeze<BR>\n" );
document.write( "20-x=ml of 60% solution remaining<BR>\n" );
document.write( "..<BR>\n" );
document.write( "60%(20-x)+100%x=70%*20<BR>\n" );
document.write( "12-0.6x+x=14<BR>\n" );
document.write( "0.4x=2<BR>\n" );
document.write( "x=5 ml<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "ml of 60% solution to be drained and replaced with 100% antifreeze=5 </SPAN>\n" );
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