document.write( "Question 569183: Please help!!I have been working on these for hours.
\n" ); document.write( "Solve each equation:\r
\n" ); document.write( "\n" ); document.write( "a. ln(2x-1)=3
\n" ); document.write( "b. log x = 1/10,000
\n" ); document.write( "c. ln(2x-1) = 3
\n" ); document.write( "d. ln(x+3) = 1\r
\n" ); document.write( "\n" ); document.write( "Thank you so much!!
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Algebra.Com's Answer #367244 by Tatiana_Stebko(1539)\"\" \"About 
You can put this solution on YOUR website!
a. \"ln%282x-1%29=3\"
\n" ); document.write( "If \"ln%28a%29=b\", then \"a=e%5Eb\"
\n" ); document.write( "\"2x-1=e%5E3\" add 1 to the both sides of the equation\r
\n" ); document.write( "\n" ); document.write( "\"2x=e%5E3%2B1\" divide by 2
\n" ); document.write( "\"x=%28e%5E3%2B1%29%2F2\"
\n" ); document.write( "use scientific calculator \"x=10.54\"\r
\n" ); document.write( "\n" ); document.write( " b. \"log+x+=+1%2F10000\"
\n" ); document.write( "If \"log%28a%29=b\", then \"a=10%5Eb\"
\n" ); document.write( "\"x+=+10%5E%281%2F10000%29\"\r
\n" ); document.write( "\n" ); document.write( "d. \"ln%28x%2B3%29+=+1+\"
\n" ); document.write( "\"x%2B3=e%5E1\"
\n" ); document.write( "\"x=e-3\"
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