document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=569018>Question 569018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One leg of a right traingle is 3 inches shorter than the hypotenuse. The other leg is equal to 8 inches. How long is the first leg?\r<BR>\n" );
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document.write( "The correct answer is 55/6 inches, but I can't figure out how ot get it. Please help me! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367196 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One leg of a right traingle is 3 inches shorter than the hypotenuse. The other leg is equal to 8 inches. How long is the first leg? <BR>\n" );
document.write( "leg 1 : 8 <BR>\n" );
document.write( "hypotenuse : x<BR>\n" );
document.write( "leg 2 : x-3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Pythagoras:<BR>\n" );
document.write( "8^2 + (x-3)^2 = x^2<BR>\n" );
document.write( "64 + x^2-6x+9 = x^2<BR>\n" );
document.write( "6x = 73<BR>\n" );
document.write( "x = 73/6 (hypotenuse)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x-3 = (73/6)-(18/6) = 55/6<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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