document.write( "Question 568975: 3. A wire 100 inches long is bent into a rectangle. If the width is
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\n" ); document.write( "4. What must be the dimensions of the rectangle so that area is a
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\n" ); document.write( "5. What is the maximum area possible?
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Algebra.Com's Answer #367195 by htmentor(1343)\"\" \"About 
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3. A wire 100 inches long is bent into a rectangle. If the width is
\n" ); document.write( "x,
\n" ); document.write( "3. How is length represented? What is the function for area?
\n" ); document.write( "4. What must be the dimensions of the rectangle so that area is a
\n" ); document.write( "maximum?
\n" ); document.write( "5. What is the maximum area possible?
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\n" ); document.write( "The perimeter P = 2(l+x) = 100
\n" ); document.write( "So l+x = 50 -> l = 50-x
\n" ); document.write( "The area, A = l*x = x(50-x) = 50x - x^2
\n" ); document.write( "To maximize the area, set dA/dx = 0:
\n" ); document.write( "dA/dx = 50 - 2x = 0
\n" ); document.write( "This gives x = 25, which means the length is also 25, so the area is maximized when it is a square
\n" ); document.write( "The maximum area is 25*25 = 625 in^2
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