document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=568922>Question 568922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the exact values of sin13/6&#960;, cos13/6&#960;, and tan13/6&#960;.\r<BR>\n" );
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document.write( "Just not sure what method to use to solve this~ <BR>\n" );
document.write( "Thanks :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367177 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the exact values of sin13/6&#960;, cos13/6&#960;, and tan13/6&#960;. <BR>\n" );
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document.write( "(13/6&#960;)=(13&#960;/6)=(12&#960;/6+&#960;/6)=(2&#960;+&#960;/6)\r<BR>\n" );
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document.write( "..<BR>\n" );
document.write( "sin(13&#960;/6)=sin(2&#960;+&#960;/6)=sin(&#960;/6)=1/2<BR>\n" );
document.write( "cos(13&#960;/6)=sin(2&#960;+&#960;/6)=cos(&#960;/6)=&#8730;3/2<BR>\n" );
document.write( "tan(13&#960;/6)=tan(2&#960;+&#960;/6)=tan(&#960;/6)=&#8730;3/3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "you could have use the trig addition formulas for sin, cos and tan, and you would get the same answers.<BR>\n" );
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